# Spider-Man Homecoming

# The Movie

Spider-Man: Homecoming is yet another recent reboot of the series. It follows the high school life of a young Peter Parker as he tries to live a normal life while also fighting crime as a secret superhero.

## Web Shooting

Spider-Man is able to move through the city by shooting web out of his hands and swinging from buildings.

If the web is shot out like a projectile (that is, it isn’t powered itself), we can work out the velocity it would need to reach 100 metres vertically up into the air:

*Velocity required = sqrt(2 × g × h)*

*Velocity required = sqrt(2 × 9.81 × 100)*

*Velocity required = 44.29 m/s*

*Velocity required = 159.5 km/hr*

## Lifting Heavy Objects with Spider Web

Spider-Man is shown to be able to lift heavy objects like cars throughout all the movie series. You may have heard that spider web is incredibly strong – but how much would you need to lift up a car?

The tensile strength of spider web is about 1000 Megapascals (MPa) [1]. This strength rating means it can support a load of 1 billion Newtons on a spider web with a cross-sectional area of 1 square metre.

A heavy car might weigh 2000 kg. We can work out the web diameter needed to hold the car up:

*Web cross-sectional area = πr ^{2}*

*Web load capacity = 1 × 10 ^{9} × πr^{2}*

where the area is given in square metres.

A 2000 kg car requires 9.81 × 2000 = 19620 Newtons of force to hold it up.

*Web load capacity = 1 × 10 ^{9} × πr^{2}*

*19620 = 1 × 10 ^{9} × πr^{2}*

*r = 0.0025 m*

So you’d need a web with a diameter of 5 mm to hold up a car.

## Spider Web Supply

When Spider-Man goes off for a journey across the city, he needs to have enough spider web with him to last the journey. Let’s say he has to go 5 km across town and then 5km back again, and that he has to shoot a 100-metre-long web every 200 metres to swing from the next building.

Spider web has a density of about 1.3 grams per cubic centimetre, or 1300 kg per cubic metre. Let’s assume he’s shooting webs with a diameter of 3 mm. How much spider web will he need to have with him at the beginning of the journey?

*Total web weight = #shots × volume per shot × density*

Let’s work out the #shots first:

*#shots = distance / distance between shots*

*#shots = (5 + 5) / 0.2*

*#shots = 50*

Now work out the volume per shot:

*Volume per shot = length × cross-sectional area*

*Volume per shot = length × πr ^{2}*

*Volume per shot = 100 × π × 0.0015 ^{2}*

*Volume per shot = 0.0007069 m ^{3}*

Put it all together:

*Total web weight = #shots × volume per shot × density*

*Total web weight = 50 × 0.0007069 × 1300 kg/m ^{3}*

*Total web weight = 45.95 kg*

That’s a fair amount of extra weight to carry while flying through the air!